3z+4(z+1)-12=-5z+16

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Solution for 3z+4(z+1)-12=-5z+16 equation: 



3z+4(z+1)-12=-5z+16

We move all terms to the left:

3z+4(z+1)-12-(-5z+16)=0

We multiply parentheses

3z+4z-(-5z+16)+4-12=0

We get rid of parentheses

3z+4z+5z-16+4-12=0

We add all the numbers together, and all the variables

12z-24=0

We move all terms containing z to the left, all other terms to the right

12z=24

z=24/12

z=2

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