3z+40=7z+4

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Solution for 3z+40=7z+4 equation: 



3z+40=7z+4

We move all terms to the left:

3z+40-(7z+4)=0

We get rid of parentheses

3z-7z-4+40=0

We add all the numbers together, and all the variables

-4z+36=0

We move all terms containing z to the left, all other terms to the right

-4z=-36

z=-36/-4

z=+9

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