3z+4=+2z+23/2

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Solution for 3z+4=+2z+23/2 equation: 



3z+4=+2z+23/2

We move all terms to the left:

3z+4-(+2z+23/2)=0

We get rid of parentheses

3z-2z+4-23/2=0

We multiply all the terms by the denominator


3z*2-2z*2-23+4*2=0

We add all the numbers together, and all the variables

3z*2-2z*2-15=0

Wy multiply elements

6z-4z-15=0

We add all the numbers together, and all the variables

2z-15=0

We move all terms containing z to the left, all other terms to the right

2z=15

z=15/2

z=7+1/2

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