3z+5=4(z+2)+2z

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Solution for 3z+5=4(z+2)+2z equation: 



3z+5=4(z+2)+2z

We move all terms to the left:

3z+5-(4(z+2)+2z)=0



We calculate terms in parentheses: -(4(z+2)+2z), so:

4(z+2)+2z

We add all the numbers together, and all the variables

2z+4(z+2)

We multiply parentheses

2z+4z+8

We add all the numbers together, and all the variables

6z+8

Back to the equation:

-(6z+8)



We get rid of parentheses

3z-6z-8+5=0

We add all the numbers together, and all the variables

-3z-3=0

We move all terms containing z to the left, all other terms to the right

-3z=3

z=3/-3

z=-1

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