3z+6(z-5)=48

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Solution for 3z+6(z-5)=48 equation: 



3z+6(z-5)=48

We move all terms to the left:

3z+6(z-5)-(48)=0

We multiply parentheses

3z+6z-30-48=0

We add all the numbers together, and all the variables

9z-78=0

We move all terms containing z to the left, all other terms to the right

9z=78

z=78/9

z=8+2/3

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