3z+6=6(z-3)+z

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Solution for 3z+6=6(z-3)+z equation: 



3z+6=6(z-3)+z

We move all terms to the left:

3z+6-(6(z-3)+z)=0



We calculate terms in parentheses: -(6(z-3)+z), so:

6(z-3)+z

We add all the numbers together, and all the variables

z+6(z-3)

We multiply parentheses

z+6z-18

We add all the numbers together, and all the variables

7z-18

Back to the equation:

-(7z-18)



We get rid of parentheses

3z-7z+18+6=0

We add all the numbers together, and all the variables

-4z+24=0

We move all terms containing z to the left, all other terms to the right

-4z=-24

z=-24/-4

z=+6

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