3z+8z-12=7z-4z+16

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Solution for 3z+8z-12=7z-4z+16 equation: 



3z+8z-12=7z-4z+16

We move all terms to the left:

3z+8z-12-(7z-4z+16)=0

We add all the numbers together, and all the variables

3z+8z-(3z+16)-12=0

We add all the numbers together, and all the variables

11z-(3z+16)-12=0

We get rid of parentheses

11z-3z-16-12=0

We add all the numbers together, and all the variables

8z-28=0

We move all terms containing z to the left, all other terms to the right

8z=28

z=28/8

z=3+1/2

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