3z+9(3+z)+3=4(5+z)+6-4Z

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Solution for 3z+9(3+z)+3=4(5+z)+6-4Z equation: 



3z+9(3+z)+3=4(5+z)+6-4

We move all terms to the left:

3z+9(3+z)+3-(4(5+z)+6-4)=0

We add all the numbers together, and all the variables

3z+9(z+3)-(4(z+5)+6-4)+3=0

We multiply parentheses

3z+9z-(4(z+5)+6-4)+27+3=0



We calculate terms in parentheses: -(4(z+5)+6-4), so:

4(z+5)+6-4

We add all the numbers together, and all the variables

4(z+5)+2

We multiply parentheses

4z+20+2

We add all the numbers together, and all the variables

4z+22

Back to the equation:

-(4z+22)



We add all the numbers together, and all the variables

12z-(4z+22)+30=0

We get rid of parentheses

12z-4z-22+30=0

We add all the numbers together, and all the variables

8z+8=0

We move all terms containing z to the left, all other terms to the right

8z=-8

z=-8/8

z=-1

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