3z-(12-z)=-2(6-2z)

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Solution for 3z-(12-z)=-2(6-2z) equation:


Simplifying
3z + -1(12 + -1z) = -2(6 + -2z)
3z + (12 * -1 + -1z * -1) = -2(6 + -2z)
3z + (-12 + 1z) = -2(6 + -2z)

Reorder the terms:
-12 + 3z + 1z = -2(6 + -2z)

Combine like terms: 3z + 1z = 4z
-12 + 4z = -2(6 + -2z)
-12 + 4z = (6 * -2 + -2z * -2)
-12 + 4z = (-12 + 4z)

Add '12' to each side of the equation.
-12 + 12 + 4z = -12 + 12 + 4z

Combine like terms: -12 + 12 = 0
0 + 4z = -12 + 12 + 4z
4z = -12 + 12 + 4z

Combine like terms: -12 + 12 = 0
4z = 0 + 4z
4z = 4z

Add '-4z' to each side of the equation.
4z + -4z = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 4z + -4z

Combine like terms: 4z + -4z = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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