3z-(13z+9)=9+(9z+8)

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Solution for 3z-(13z+9)=9+(9z+8) equation: 



3z-(13z+9)=9+(9z+8)

We move all terms to the left:

3z-(13z+9)-(9+(9z+8))=0

We get rid of parentheses

3z-13z-(9+(9z+8))-9=0



We calculate terms in parentheses: -(9+(9z+8)), so:

9+(9z+8)

determiningTheFunctionDomain
(9z+8)+9

We get rid of parentheses

9z+8+9

We add all the numbers together, and all the variables

9z+17

Back to the equation:

-(9z+17)



We add all the numbers together, and all the variables

-10z-(9z+17)-9=0

We get rid of parentheses

-10z-9z-17-9=0

We add all the numbers together, and all the variables

-19z-26=0

We move all terms containing z to the left, all other terms to the right

-19z=26

z=26/-19

z=-1+7/19

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