3z-(z/2+5)=10

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Solution for 3z-(z/2+5)=10 equation: 



3z-(z/2+5)=10

We move all terms to the left:

3z-(z/2+5)-(10)=0

We get rid of parentheses

3z-z/2-5-10=0

We multiply all the terms by the denominator


3z*2-z-5*2-10*2=0

We add all the numbers together, and all the variables

-1z+3z*2-30=0

Wy multiply elements

-1z+6z-30=0

We add all the numbers together, and all the variables

5z-30=0

We move all terms containing z to the left, all other terms to the right

5z=30

z=30/5

z=6

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