3z-(z/2+5)=10

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Solution for 3z-(z/2+5)=10 equation:



3z-(z/2+5)=10
We move all terms to the left:
3z-(z/2+5)-(10)=0
We get rid of parentheses
3z-z/2-5-10=0
We multiply all the terms by the denominator
3z*2-z-5*2-10*2=0
We add all the numbers together, and all the variables
-1z+3z*2-30=0
Wy multiply elements
-1z+6z-30=0
We add all the numbers together, and all the variables
5z-30=0
We move all terms containing z to the left, all other terms to the right
5z=30
z=30/5
z=6

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