3z-12z+4=16-28

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Solution for 3z-12z+4=16-28 equation: 



3z-12z+4=16-28

We move all terms to the left:

3z-12z+4-(16-28)=0

We add all the numbers together, and all the variables

3z-12z+4-(-12)=0

We add all the numbers together, and all the variables

-9z+16=0

We move all terms containing z to the left, all other terms to the right

-9z=-16

z=-16/-9

z=1+7/9

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