3z-14+2z=z+50

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Solution for 3z-14+2z=z+50 equation: 



3z-14+2z=z+50

We move all terms to the left:

3z-14+2z-(z+50)=0

We add all the numbers together, and all the variables

5z-(z+50)-14=0

We get rid of parentheses

5z-z-50-14=0

We add all the numbers together, and all the variables

4z-64=0

We move all terms containing z to the left, all other terms to the right

4z=64

z=64/4

z=16

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