3z-18=273(z-6)=3(9)

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Solution for 3z-18=273(z-6)=3(9) equation: 



3z-18=273(z-6)=3(9)

We move all terms to the left:

3z-18-(273(z-6))=0



We calculate terms in parentheses: -(273(z-6)), so:

273(z-6)

We multiply parentheses

273z-1638

Back to the equation:

-(273z-1638)



We get rid of parentheses

3z-273z+1638-18=0

We add all the numbers together, and all the variables

-270z+1620=0

We move all terms containing z to the left, all other terms to the right

-270z=-1620

z=-1620/-270

z=+6

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