3z-2(1-z)=3(z+1)+2z

Solution for 3z-2(1-z)=3(z+1)+2z equation:

Simplifying
3z + -2(1 + -1z) = 3(z + 1) + 2z
3z + (1 * -2 + -1z * -2) = 3(z + 1) + 2z
3z + (-2 + 2z) = 3(z + 1) + 2z

Reorder the terms:
-2 + 3z + 2z = 3(z + 1) + 2z

Combine like terms: 3z + 2z = 5z
-2 + 5z = 3(z + 1) + 2z

Reorder the terms:
-2 + 5z = 3(1 + z) + 2z
-2 + 5z = (1 * 3 + z * 3) + 2z
-2 + 5z = (3 + 3z) + 2z

Combine like terms: 3z + 2z = 5z
-2 + 5z = 3 + 5z

Add '-5z' to each side of the equation.
-2 + 5z + -5z = 3 + 5z + -5z

Combine like terms: 5z + -5z = 0
-2 + 0 = 3 + 5z + -5z
-2 = 3 + 5z + -5z

Combine like terms: 5z + -5z = 0
-2 = 3 + 0
-2 = 3

Solving
-2 = 3

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.