3z-2=1+5(z+6)

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Solution for 3z-2=1+5(z+6) equation: 



3z-2=1+5(z+6)

We move all terms to the left:

3z-2-(1+5(z+6))=0



We calculate terms in parentheses: -(1+5(z+6)), so:

1+5(z+6)

determiningTheFunctionDomain
5(z+6)+1

We multiply parentheses

5z+30+1

We add all the numbers together, and all the variables

5z+31

Back to the equation:

-(5z+31)



We get rid of parentheses

3z-5z-31-2=0

We add all the numbers together, and all the variables

-2z-33=0

We move all terms containing z to the left, all other terms to the right

-2z=33

z=33/-2

z=-16+1/2

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