3z-2z+4z-4z+z=20

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Solution for 3z-2z+4z-4z+z=20 equation: 



3z-2z+4z-4z+z=20

We move all terms to the left:

3z-2z+4z-4z+z-(20)=0

We add all the numbers together, and all the variables

2z-20=0

We move all terms containing z to the left, all other terms to the right

2z=20

z=20/2

z=10

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