3z-3(z+2)=5(z-3)-6

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Solution for 3z-3(z+2)=5(z-3)-6 equation: 



3z-3(z+2)=5(z-3)-6

We move all terms to the left:

3z-3(z+2)-(5(z-3)-6)=0

We multiply parentheses

3z-3z-(5(z-3)-6)-6=0



We calculate terms in parentheses: -(5(z-3)-6), so:

5(z-3)-6

We multiply parentheses

5z-15-6

We add all the numbers together, and all the variables

5z-21

Back to the equation:

-(5z-21)



We add all the numbers together, and all the variables

-(5z-21)-6=0

We get rid of parentheses

-5z+21-6=0

We add all the numbers together, and all the variables

-5z+15=0

We move all terms containing z to the left, all other terms to the right

-5z=-15

z=-15/-5

z=+3

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