3z-4=z+12

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Solution for 3z-4=z+12 equation: 



3z-4=z+12

We move all terms to the left:

3z-4-(z+12)=0

We get rid of parentheses

3z-z-12-4=0

We add all the numbers together, and all the variables

2z-16=0

We move all terms containing z to the left, all other terms to the right

2z=16

z=16/2

z=8

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