3z-5+2z+25-5z=z

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Solution for 3z-5+2z+25-5z=z equation: 



3z-5+2z+25-5z=z

We move all terms to the left:

3z-5+2z+25-5z-(z)=0

We add all the numbers together, and all the variables

-1z+20=0

We move all terms containing z to the left, all other terms to the right

-z=-20

z=-20/-1

z=+20

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