3z-5=6-(2z-4)

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Solution for 3z-5=6-(2z-4) equation: 



3z-5=6-(2z-4)

We move all terms to the left:

3z-5-(6-(2z-4))=0



We calculate terms in parentheses: -(6-(2z-4)), so:

6-(2z-4)

determiningTheFunctionDomain
-(2z-4)+6

We get rid of parentheses

-2z+4+6

We add all the numbers together, and all the variables

-2z+10

Back to the equation:

-(-2z+10)



We get rid of parentheses

3z+2z-10-5=0

We add all the numbers together, and all the variables

5z-15=0

We move all terms containing z to the left, all other terms to the right

5z=15

z=15/5

z=3

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