3z-6(z+9)=4(z-3)-21

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Solution for 3z-6(z+9)=4(z-3)-21 equation: 



3z-6(z+9)=4(z-3)-21

We move all terms to the left:

3z-6(z+9)-(4(z-3)-21)=0

We multiply parentheses

3z-6z-(4(z-3)-21)-54=0



We calculate terms in parentheses: -(4(z-3)-21), so:

4(z-3)-21

We multiply parentheses

4z-12-21

We add all the numbers together, and all the variables

4z-33

Back to the equation:

-(4z-33)



We add all the numbers together, and all the variables

-3z-(4z-33)-54=0

We get rid of parentheses

-3z-4z+33-54=0

We add all the numbers together, and all the variables

-7z-21=0

We move all terms containing z to the left, all other terms to the right

-7z=21

z=21/-7

z=-3

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