3z-7z+15=6z+27

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Solution for 3z-7z+15=6z+27 equation: 



3z-7z+15=6z+27

We move all terms to the left:

3z-7z+15-(6z+27)=0

We add all the numbers together, and all the variables

-4z-(6z+27)+15=0

We get rid of parentheses

-4z-6z-27+15=0

We add all the numbers together, and all the variables

-10z-12=0

We move all terms containing z to the left, all other terms to the right

-10z=12

z=12/-10

z=-1+1/5

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