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3z-9=1+6(z-2)
We move all terms to the left:
3z-9-(1+6(z-2))=0
We calculate terms in parentheses: -(1+6(z-2)), so:We get rid of parentheses
1+6(z-2)
determiningTheFunctionDomain 6(z-2)+1
We multiply parentheses
6z-12+1
We add all the numbers together, and all the variables
6z-11
Back to the equation:
-(6z-11)
3z-6z+11-9=0
We add all the numbers together, and all the variables
-3z+2=0
We move all terms containing z to the left, all other terms to the right
-3z=-2
z=-2/-3
z=2/3
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