3z/7+8=1

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Solution for 3z/7+8=1 equation: 



3z/7+8=1

We move all terms to the left:

3z/7+8-(1)=0

We add all the numbers together, and all the variables

3z/7+7=0

We multiply all the terms by the denominator


3z+7*7=0

We add all the numbers together, and all the variables

3z+49=0

We move all terms containing z to the left, all other terms to the right

3z=-49

z=-49/3

z=-16+1/3

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