3z2-0.01-0.1z=0,0

Solution for 3z2-0.01-0.1z=0,0 equation:

3z^2-0.01-0.1z=0.0

a = 3; b = -0.1; c = -0.01;
Δ = b2-4ac
Δ = -0.12-4·3·(-0.01)
Δ = 0.13
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.1)-\sqrt{0.13}}{2*3}=\frac{0.1-\sqrt{0.13}}{6}
$
$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.1)+\sqrt{0.13}}{2*3}=\frac{0.1+\sqrt{0.13}}{6}
$