3z=-1+(z+1)

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Solution for 3z=-1+(z+1) equation: 



3z=-1+(z+1)

We move all terms to the left:

3z-(-1+(z+1))=0



We calculate terms in parentheses: -(-1+(z+1)), so:

-1+(z+1)

determiningTheFunctionDomain
(z+1)-1

We get rid of parentheses

z+1-1

We add all the numbers together, and all the variables

z

Back to the equation:

-(z)



We add all the numbers together, and all the variables

2z=0

z=0/2

z=0

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