3z=3(-6z+7)

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Solution for 3z=3(-6z+7) equation: 



3z=3(-6z+7)

We move all terms to the left:

3z-(3(-6z+7))=0



We calculate terms in parentheses: -(3(-6z+7)), so:

3(-6z+7)

We multiply parentheses

-18z+21

Back to the equation:

-(-18z+21)



We get rid of parentheses

3z+18z-21=0

We add all the numbers together, and all the variables

21z-21=0

We move all terms containing z to the left, all other terms to the right

21z=21

z=21/21

z=1

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