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4((14-7y)/3)-5y=10

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Solution for 4((14-7y)/3)-5y=10 equation:



4((14-7y)/3)-5y=10
We move all terms to the left:
4((14-7y)/3)-5y-(10)=0
We add all the numbers together, and all the variables
4((-7y+14)/3)-5y-10=0
We add all the numbers together, and all the variables
-5y+4((-7y+14)/3)-10=0
We multiply all the terms by the denominator
-5y*3)+4((-7y+14)-10*3)=0
We add all the numbers together, and all the variables
-5y*3)+4((-7y+14)=0
Wy multiply elements
-15y^2=0
a = -15; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-15)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:
y=\frac{-b}{2a}=\frac{0}{-30}=0

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