4((3m+2)/(2+6m))=34

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Solution for 4((3m+2)/(2+6m))=34 equation: 



4((3m+2)/(2+6m))=34

We move all terms to the left:

4((3m+2)/(2+6m))-(34)=0



Domain of the equation: (2+6m))!=0

We move all terms containing m to the left, all other terms to the right

6m)!=-2

m!=-2/1

m!=-2

m∈R



We add all the numbers together, and all the variables

4((3m+2)/(6m+2))-34=0

We multiply all the terms by the denominator


4((3m+2)-34*(6m+2))=0

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