4((3m+2)/2+6m)=34

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Solution for 4((3m+2)/2+6m)=34 equation: 



4((3m+2)/2+6m)=34

We move all terms to the left:

4((3m+2)/2+6m)-(34)=0



Domain of the equation: 2+6m)!=0

We move all terms containing m to the left, all other terms to the right

6m)!=-2

m!=-2/1

m!=-2

m∈R



We multiply all the terms by the denominator


4((3m+2)-34*2+6m)=0

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