4((3x-x)(3x-x))+27=15

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Solution for 4((3x-x)(3x-x))+27=15 equation:


Simplifying
4((3x + -1x)(3x + -1x)) + 27 = 15

Combine like terms: 3x + -1x = 2x
4((2x)(3x + -1x)) + 27 = 15

Remove parenthesis around (2x)
4(2x(3x + -1x)) + 27 = 15

Combine like terms: 3x + -1x = 2x
4(2x(2x)) + 27 = 15

Remove parenthesis around (2x)
4(2x * 2x) + 27 = 15

Reorder the terms for easier multiplication:
4(2 * 2x * x) + 27 = 15

Multiply 2 * 2
4(4x * x) + 27 = 15

Multiply x * x
4(4x2) + 27 = 15

Remove parenthesis around (4x2)
4 * 4x2 + 27 = 15

Multiply 4 * 4
16x2 + 27 = 15

Reorder the terms:
27 + 16x2 = 15

Solving
27 + 16x2 = 15

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-27' to each side of the equation.
27 + -27 + 16x2 = 15 + -27

Combine like terms: 27 + -27 = 0
0 + 16x2 = 15 + -27
16x2 = 15 + -27

Combine like terms: 15 + -27 = -12
16x2 = -12

Divide each side by '16'.
x2 = -0.75

Simplifying
x2 = -0.75

Reorder the terms:
0.75 + x2 = -0.75 + 0.75

Combine like terms: -0.75 + 0.75 = 0.00
0.75 + x2 = 0.00

The solution to this equation could not be determined.

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