4()y-1-1=2(2y-3)

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Solution for 4()y-1-1=2(2y-3) equation: 



4()y-1-1=2(2y-3)

We move all terms to the left:

4()y-1-1-(2(2y-3))=0

We add all the numbers together, and all the variables

4()y-(2(2y-3))-2=0



We calculate terms in parentheses: -(2(2y-3)), so:

2(2y-3)

We multiply parentheses

4y-6

Back to the equation:

-(4y-6)



We get rid of parentheses

4()y-4y+6-2=0

We add all the numbers together, and all the variables

-4y+4()y+4=0

We move all terms containing y to the left, all other terms to the right

-4y+4()y=-4

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