4(-10b-2)=-128

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Solution for 4(-10b-2)=-128 equation: 



4(-10b-2)=-128

We move all terms to the left:

4(-10b-2)-(-128)=0

We add all the numbers together, and all the variables

4(-10b-2)+128=0

We multiply parentheses

-40b-8+128=0

We add all the numbers together, and all the variables

-40b+120=0

We move all terms containing b to the left, all other terms to the right

-40b=-120

b=-120/-40

b=+3

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