4(-20-4f)=4(2f-23)

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Solution for 4(-20-4f)=4(2f-23) equation: 



4(-20-4f)=4(2f-23)

We move all terms to the left:

4(-20-4f)-(4(2f-23))=0

We add all the numbers together, and all the variables

4(-4f-20)-(4(2f-23))=0

We multiply parentheses

-16f-(4(2f-23))-80=0



We calculate terms in parentheses: -(4(2f-23)), so:

4(2f-23)

We multiply parentheses

8f-92

Back to the equation:

-(8f-92)



We get rid of parentheses

-16f-8f+92-80=0

We add all the numbers together, and all the variables

-24f+12=0

We move all terms containing f to the left, all other terms to the right

-24f=-12

f=-12/-24

f=1/2

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