4(-2x-4+5x)=6(7+3x)

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Solution for 4(-2x-4+5x)=6(7+3x) equation: 



4(-2x-4+5x)=6(7+3x)

We move all terms to the left:

4(-2x-4+5x)-(6(7+3x))=0

We add all the numbers together, and all the variables

4(3x-4)-(6(3x+7))=0

We multiply parentheses

12x-(6(3x+7))-16=0



We calculate terms in parentheses: -(6(3x+7)), so:

6(3x+7)

We multiply parentheses

18x+42

Back to the equation:

-(18x+42)



We get rid of parentheses

12x-18x-42-16=0

We add all the numbers together, and all the variables

-6x-58=0

We move all terms containing x to the left, all other terms to the right

-6x=58

x=58/-6

x=-9+2/3

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