4(-2y+2)+2(5y-2)=6

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Solution for 4(-2y+2)+2(5y-2)=6 equation: 



4(-2y+2)+2(5y-2)=6

We move all terms to the left:

4(-2y+2)+2(5y-2)-(6)=0

We multiply parentheses

-8y+10y+8-4-6=0

We add all the numbers together, and all the variables

2y-2=0

We move all terms containing y to the left, all other terms to the right

2y=2

y=2/2

y=1

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