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4(-3(-2n-10/2)+4n=5(n+12)
We move all terms to the left:
4(-3(-2n-10/2)+4n-(5(n+12))=0
Domain of the equation: 2)+4n-(5(n+12))!=0We add all the numbers together, and all the variables
n∈R
4(-3(-2n-5)+4n-(5(n+12))=0
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