4(-3-y)=2(3y+24)

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Solution for 4(-3-y)=2(3y+24) equation: 



4(-3-y)=2(3y+24)

We move all terms to the left:

4(-3-y)-(2(3y+24))=0

We add all the numbers together, and all the variables

4(-1y-3)-(2(3y+24))=0

We multiply parentheses

-4y-(2(3y+24))-12=0



We calculate terms in parentheses: -(2(3y+24)), so:

2(3y+24)

We multiply parentheses

6y+48

Back to the equation:

-(6y+48)



We get rid of parentheses

-4y-6y-48-12=0

We add all the numbers together, and all the variables

-10y-60=0

We move all terms containing y to the left, all other terms to the right

-10y=60

y=60/-10

y=-6

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