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4(-3/2v+1)-6=5v-(11v+1)
We move all terms to the left:
4(-3/2v+1)-6-(5v-(11v+1))=0
Domain of the equation: 2v+1)!=0We multiply parentheses
v∈R
-12v-(5v-(11v+1))+4-6=0
We calculate terms in parentheses: -(5v-(11v+1)), so:We add all the numbers together, and all the variables
5v-(11v+1)
We get rid of parentheses
5v-11v-1
We add all the numbers together, and all the variables
-6v-1
Back to the equation:
-(-6v-1)
-12v-(-6v-1)-2=0
We get rid of parentheses
-12v+6v+1-2=0
We add all the numbers together, and all the variables
-6v-1=0
We move all terms containing v to the left, all other terms to the right
-6v=1
v=1/-6
v=-1/6
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