4(-3q-3)=7q+9(-2q+6)

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Solution for 4(-3q-3)=7q+9(-2q+6) equation: 



4(-3q-3)=7q+9(-2q+6)

We move all terms to the left:

4(-3q-3)-(7q+9(-2q+6))=0

We multiply parentheses

-12q-(7q+9(-2q+6))-12=0



We calculate terms in parentheses: -(7q+9(-2q+6)), so:

7q+9(-2q+6)

We multiply parentheses

7q-18q+54

We add all the numbers together, and all the variables

-11q+54

Back to the equation:

-(-11q+54)



We get rid of parentheses

-12q+11q-54-12=0

We add all the numbers together, and all the variables

-1q-66=0

We move all terms containing q to the left, all other terms to the right

-q=66

q=66/-1

q=-66

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