4(-3x-2)+10=2(1-6x)

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Solution for 4(-3x-2)+10=2(1-6x) equation: 



4(-3x-2)+10=2(1-6x)

We move all terms to the left:

4(-3x-2)+10-(2(1-6x))=0

We add all the numbers together, and all the variables

4(-3x-2)-(2(-6x+1))+10=0

We multiply parentheses

-12x-(2(-6x+1))-8+10=0



We calculate terms in parentheses: -(2(-6x+1)), so:

2(-6x+1)

We multiply parentheses

-12x+2

Back to the equation:

-(-12x+2)



We add all the numbers together, and all the variables

-12x-(-12x+2)+2=0

We get rid of parentheses

-12x+12x-2+2=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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