4(-4z-3)=3z+7(-6z-5)

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Solution for 4(-4z-3)=3z+7(-6z-5) equation:



4(-4z-3)=3z+7(-6z-5)
We move all terms to the left:
4(-4z-3)-(3z+7(-6z-5))=0
We multiply parentheses
-16z-(3z+7(-6z-5))-12=0
We calculate terms in parentheses: -(3z+7(-6z-5)), so:
3z+7(-6z-5)
We multiply parentheses
3z-42z-35
We add all the numbers together, and all the variables
-39z-35
Back to the equation:
-(-39z-35)
We get rid of parentheses
-16z+39z+35-12=0
We add all the numbers together, and all the variables
23z+23=0
We move all terms containing z to the left, all other terms to the right
23z=-23
z=-23/23
z=-1

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