4(-7b-5)-8(-3-2b)=52

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Solution for 4(-7b-5)-8(-3-2b)=52 equation: 



4(-7b-5)-8(-3-2b)=52

We move all terms to the left:

4(-7b-5)-8(-3-2b)-(52)=0

We add all the numbers together, and all the variables

4(-7b-5)-8(-2b-3)-52=0

We multiply parentheses

-28b+16b-20+24-52=0

We add all the numbers together, and all the variables

-12b-48=0

We move all terms containing b to the left, all other terms to the right

-12b=48

b=48/-12

b=-4

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