4(-7x+2)=-3(-2+9x)+68/2

Solution for 4(-7x+2)=-3(-2+9x)+68/2 equation:

4(-7x+2)=-3(-2+9x)+68/2

We move all terms to the left:

4(-7x+2)-(-3(-2+9x)+68/2)=0

We add all the numbers together, and all the variables

4(-7x+2)-(-3(9x-2)+68/2)=0

We multiply parentheses

-28x-(-3(9x-2)+68/2)+8=0

We multiply all the terms by the denominator


-28x*2)-(-3(9x-2)+68+8*2)=0

We add all the numbers together, and all the variables

-28x*2)-(-3(9x-2)=0

We multiply parentheses

-28x*2)-(-27x+6=0

Wy multiply elements

-56x^2-27x+6=0

a = -56; b = -27; c = +6;
Δ = b2-4ac
Δ = -272-4·(-56)·6
Δ = 2073
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-27)-\sqrt{2073}}{2*-56}=\frac{27-\sqrt{2073}}{-112}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-27)+\sqrt{2073}}{2*-56}=\frac{27+\sqrt{2073}}{-112}
$