4(-8b-)=-4(b+1)1

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Solution for 4(-8b-)=-4(b+1)1 equation: 



4(-8b-)=-4(b+1)1

We move all terms to the left:

4(-8b-)-(-4(b+1)1)=0

We add all the numbers together, and all the variables

4(-8b)-(-4(b+1)1)=0

We multiply parentheses

-32b-(-4(b+1)1)=0



We calculate terms in parentheses: -(-4(b+1)1), so:

-4(b+1)1

We multiply parentheses

-4b-4

Back to the equation:

-(-4b-4)



We get rid of parentheses

-32b+4b+4=0

We add all the numbers together, and all the variables

-28b+4=0

We move all terms containing b to the left, all other terms to the right

-28b=-4

b=-4/-28

b=1/7

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