4(-a+1)=7-3(2a-5)

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Solution for 4(-a+1)=7-3(2a-5) equation: 



4(-a+1)=7-3(2a-5)

We move all terms to the left:

4(-a+1)-(7-3(2a-5))=0

We add all the numbers together, and all the variables

4(-1a+1)-(7-3(2a-5))=0

We multiply parentheses

-4a-(7-3(2a-5))+4=0



We calculate terms in parentheses: -(7-3(2a-5)), so:

7-3(2a-5)

determiningTheFunctionDomain
-3(2a-5)+7

We multiply parentheses

-6a+15+7

We add all the numbers together, and all the variables

-6a+22

Back to the equation:

-(-6a+22)



We get rid of parentheses

-4a+6a-22+4=0

We add all the numbers together, and all the variables

2a-18=0

We move all terms containing a to the left, all other terms to the right

2a=18

a=18/2

a=9

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