4(-m+2)+2m=-12(10-12m)-3

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Solution for 4(-m+2)+2m=-12(10-12m)-3 equation: 



4(-m+2)+2m=-12(10-12m)-3

We move all terms to the left:

4(-m+2)+2m-(-12(10-12m)-3)=0

We add all the numbers together, and all the variables

4(-1m+2)+2m-(-12(-12m+10)-3)=0

We add all the numbers together, and all the variables

2m+4(-1m+2)-(-12(-12m+10)-3)=0

We multiply parentheses

2m-4m-(-12(-12m+10)-3)+8=0



We calculate terms in parentheses: -(-12(-12m+10)-3), so:

-12(-12m+10)-3

We multiply parentheses

144m-120-3

We add all the numbers together, and all the variables

144m-123

Back to the equation:

-(144m-123)



We add all the numbers together, and all the variables

-2m-(144m-123)+8=0

We get rid of parentheses

-2m-144m+123+8=0

We add all the numbers together, and all the variables

-146m+131=0

We move all terms containing m to the left, all other terms to the right

-146m=-131

m=-131/-146

m=131/146

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