4(-n-1)=2(2n+1)+2

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Solution for 4(-n-1)=2(2n+1)+2 equation: 



4(-n-1)=2(2n+1)+2

We move all terms to the left:

4(-n-1)-(2(2n+1)+2)=0

We add all the numbers together, and all the variables

4(-1n-1)-(2(2n+1)+2)=0

We multiply parentheses

-4n-(2(2n+1)+2)-4=0



We calculate terms in parentheses: -(2(2n+1)+2), so:

2(2n+1)+2

We multiply parentheses

4n+2+2

We add all the numbers together, and all the variables

4n+4

Back to the equation:

-(4n+4)



We get rid of parentheses

-4n-4n-4-4=0

We add all the numbers together, and all the variables

-8n-8=0

We move all terms containing n to the left, all other terms to the right

-8n=8

n=8/-8

n=-1

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