4(0.1-x)(0.2-x)=x

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Solution for 4(0.1-x)(0.2-x)=x equation:



4(0.1-x)(0.2-x)=x
We move all terms to the left:
4(0.1-x)(0.2-x)-(x)=0
We add all the numbers together, and all the variables
4(-1x+0.1)(-1x+0.2)-x=0
We add all the numbers together, and all the variables
-1x+4(-1x+0.1)(-1x+0.2)=0
We multiply parentheses ..
4(+x^2-0.2x-0.1x+0.02)-1x=0
We multiply parentheses
4x^2+0x+0x-1x+0.08=0
We add all the numbers together, and all the variables
4x^2+x+0.08=0
a = 4; b = 1; c = +0.08;
Δ = b2-4ac
Δ = 12-4·4·0.08
Δ = -0.28
Delta is less than zero, so there is no solution for the equation

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